1/6/2024 0 Comments For i in dict pythonHow does the in operator work with dict.keys()?.If the dict.keys() doesn't return a list, then what does it return?.How does the first case "know" that the key doesn't exist? I understand when you try to access a key that doesn't exist, python gives an error, so I'm assuming that's the same mechanism?.Key_method_time = key_method.timeit(1000) In_op = Timer("x in d", "from _main_ import x, d") # I thought that the second method would take longer and longer as the dictionary grew, but that doesn't seem to be the case # basically I'm running both methods and checking how much time each takes as the dictionary grows my code and its results are below: # checking time complexity of dict key look up methods I did further testing with the timeit module. I was confused because these two methods took around the same time on leetcode, and I thought the second method would have a time complexity of O(n) because (I thought) it was just a list. # where n is a key, and d.keys() is a viewing object (a list?) Particularly in comparing these two lines of code: # where n is a key, and d is a dictionary Can someone explain to me how exactly python "looks up" a dictionary key to see if it exists. This involved a "look up" to see if a dictionary key existed. I'm going over the Two Sum problem on LeetCode, and the optimal solution was to use a dictionary.
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